Respuesta:
1)
Areasombreada = Área del círculo - Area del cuadrado
As= Aci - Ac
Aci = π*r² = π*(3)² = 9π cm²
Ac = L² = 2² = 4cm²
As= 9π - 4 ≈ 24,27 cm²
nota: 9*π ≈ 28,27
2)
As = Asemicirculo + Arectangulo
Asemicirculo = (π*r²)/2 = (π*6²)/2 = 36π/2 = 18π
Arectangulo = b*h = 3*2 = 6
As = 18π + 6 ≈ 62,54
nota: 18π ≈ 56,54
