Respuesta:
a)
[tex]y_{max} = \frac{v_{0}^{2} \sin^{2} ( \theta ) }{2g} [/tex]
[tex]y_{max} = \frac{{(12 \frac{m}{s}) }^{2} \sin^{2} (30°) }{2(9.8 \frac{m}{ {s}^{2} } )} [/tex]
[tex]y_{max} = 1.84 \: m[/tex]
b)
[tex]t = \frac{2v_{0} \sin( \theta ) }{g} [/tex]
[tex]t = \frac{2(12 \frac{m}{s} ) \sin( 30°) }{9.8 \frac{m}{ {s}^{2} } } [/tex]
[tex]t = 1.22 \: s[/tex]
c)
[tex]alcance = x_{max}[/tex]
[tex]x_{max} = \frac{v_{0}^{2} \sin(2 \theta) }{g} [/tex]
[tex]x_{max} = \frac{(12 \frac{m}{s} )^{2} \sin(2 \times 30° ) }{9.8 \frac{m}{ {s}^{2} } } [/tex]
[tex]x_{max} = 12.73 \: m[/tex]
Espero te sea de ayuda, coronita por fis
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