[tex]masa \: H_{2}O=500 \: g \\ \\ masa \: molar \: H_{2}O= 18 \: g/mol [/tex]
[tex]500 \: g \:H_{2}O \times \frac{1 \: mol \:H_{2}O}{18 \: g/mol \: H_{2}O} \\ \\ = \frac{500 \: mol \: H_{2}O }{18} = \boxed{ \boxed{27.8 \: mol \: H_{2}O}}[/tex]