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Si: tg(α + β) = 3 y tgβ = 2
Calcular: tgα


Respuesta :

Explicación paso a paso:

[tex]tan( \alpha + \beta ) = \frac{tan \alpha + \tan( \beta ) }{1 - \tan( \alpha ) \tan( \beta ) } [/tex]

[tex]3 = \frac{ \tan( \alpha ) + 2}{1 - \tan( \alpha ) 2} [/tex]

[tex]3 - 6 \tan( \alpha ) = \tan( \alpha ) + 2 \\ 1 = 7 \tan( \alpha ) \\ \frac{1}{7} = \tan( \alpha ) [/tex]