Respuesta:
a) [tex]\frac{1}{x}+\frac{x+1}{x}-\frac{x^2+x-1}{x}=\frac{-x^2+3}{x}[/tex]
b) [tex]\frac{1}{x}+\frac{x+1}{x^2}=\frac{2x+1}{x^2}[/tex]
c) [tex]\frac{x}{x^2-1}+\frac{x-2}{x+1}=\frac{x^2-2x+2}{\left(x+1\right)\left(x-1\right)}[/tex]
d) [tex]\frac{2}{x^2-9}-\frac{7x}{x-3}+3=\frac{-4x^2-21x-25}{\left(x+3\right)\left(x-3\right)}[/tex]
pásate por mi canal de YT Benja Rey Mathcoach
saludos
