Respuesta :
Respuesta:
f(x) = ( 3x^2+1 )( x-3 )
f(x) = 3x^2(x-3)+1(x-3)
f(x) = 3x^3-9x^2+x-3
f ' (x) = d/dx [ ( 3x^3-9x^2+x-3 ) ]
f ' (x) = d/dx [ ( 3x^3 ) ] - d/dx [ ( 9x^2 ) ] + d/dx [ (x) ] - d/dx [ (3) ]
f ' (x) = ( 3×(d/dx[(x^3)]-(9×d/dx[(x^2)])+1-0
f ' (x) = 3(3(x)^(3-1))-(9(2(x)^(2-1)))+1
f ' (x) = 3(3x^2)-9(2x)+1
f ' (x) = 9x^2-18x+1
R// La derivada de la función f(x) = ( 3x^2+1 ) ( x-3 ) es f ' (x) = 9x^2-18x+1
Explicación paso a paso: