Respuesta:
[tex] {a}^{2} + {b}^{2} = {c}^{2} \\ {a} = \sqrt{ {13}^{2} - {5}^{2} } \\ a = \sqrt[]{169 - 25} \\ a = \sqrt[]{144} \\ a = 12 \\ \\ \\ \\ [/tex]
Sen A= 5/15
cos A=12/13
tang A=5/12
Cot A=12/5.
Sec A= 13/12.
CoscA=15/5
2.
[tex] {c}^{2} = {91}^{2} + {60}^{2} \\ \\ {c}^{2 = 8281 + 3600 } \\ {c}^{2} = 11881 \\ {c} = \sqrt[]{11881} \\ c = 109 [/tex]
SenA=60/109
CosA=91/109
TanA=60/91
CotA=91/60
SecA=109/91
CoscA=109/60
Dame corona y le hago la tres es que son muy largas...
