Giselarp01go Giselarp01go Matemáticas contestada Sabiendo que: xy[tex]xy=ax^{2\sqrt{2} }[/tex] , [tex]yz=ax^{3\sqrt{2} }[/tex] y [tex]xz= ax^{6\sqrt{2} }[/tex] Simplificar: [tex](A × B)^{(\sqrt{2}-1 }[/tex] Donde: A= [tex]\sqrt[4]{x × \sqrt[3\sqrt{2} ]{y} × \sqrt{z}}[/tex] B= [tex]\sqrt[4]{y × \sqrt[3\sqrt{2} ]{z} × \sqrt{x} }[/tex]