Explicación paso a paso:
12xyz + xyz = xyz(12 + 1) = 13xyz
[tex]\frac{1}{6} m^{2} n[/tex]
[tex]z^{3}(-3+4) =z^{3}[/tex]
[tex]ab(\frac{-4}{5}+2 ) =\frac{8}{5}ab[/tex]
[tex]x^{3} y^{2} (-2+11)=9x^{3} y^{2}[/tex]
[tex]a^{2} m^{2}(3-8) =-5a^{2} m^{2}[/tex]
[tex]a^{3} b^{3} c(15+19)=34a^{3} b^{3} c[/tex]
[tex]xy^{3} (5+4)=9xy^{3}[/tex]
Mi coronita plz ;p
Ayudaria mucho q escribieras los ejercicios,
