Resuelva las siguientes operaciones combinadas
Doy corona ayuda

Respuesta:
[tex] \frac{8}{6} + \frac{3}{5} \times \frac{10}{6} - \frac{2}{3} = \\ \frac{8}{6} + \frac{30}{30} - \frac{2}{3} = \\ \frac{8}{6} + 1 - \frac{2}{3} = \frac{8 + 6 - 4}{6} = \frac{10}{6} = \frac{5}{3} [/tex]
[tex] \frac{5}{4} + \frac{3}{3} \times \frac{5}{2} \div \frac{10}{4} = \\ \frac{5}{4} + 1 \times \frac{5}{2} \div \frac{5}{2} = \\ \frac{5}{4} + \frac{5}{2} \div \frac{5}{2} = \\ \frac{5}{4} + \frac{10}{10} = \\ \frac{5}{4} + 1 = \frac{5 + 4}{4} = \frac{9}{4} [/tex]
[tex] \frac{2}{6} \div \frac{6}{18} - \frac{5}{6} + \frac{2}{3} = \\ \frac{1}{3} \div \frac{1}{3} - \frac{5}{6} + \frac{2}{3} = \\ \frac{3}{3} - \frac{5}{6} + \frac{2}{3} = \\ 1 - \frac{5}{6} + \frac{2}{3} = \frac{6 - 5 + 4}{6} = \frac{5}{6} [/tex]
[tex] \frac{5}{7} + \frac{6}{2} \times - \frac{4}{3} - \frac{1}{2} = \\ \frac{5}{7} + 3 \times \frac{4}{3} - \frac{1}{2} = \\ \frac{5}{7} + \frac{12}{3} - \frac{1}{2} = \\ \frac{5}{7} + 4 - \frac{1}{2} = \frac{10 + 56 - 7}{14} = \frac{59}{14} [/tex]