Respuesta:
[tex]a)\frac{x}{-9}+\frac{y}{8}=1\\\\b)\frac{x}{-10}+\frac{y}{-8}=1[/tex]
Explicación paso a paso:
Forma simétrica:
[tex]\frac{x}{a} +\frac{y}{b}=1\\\\1)-8x + 9y-72=0 \\\\8x-9y+72=0\\\\8x-9y=-72\\\\\frac{8x}{-72} -\frac{9y}{-72} =\frac{-72}{-72}\\\\\frac{x}{-9} +\frac{y}{8}=1[/tex]
[tex]b)-4x-5y-40=0\\\\4x + 5y + 40 = 0\\\\4x+5y=-40\\\\\frac{4x}{-40} +\frac{5y}{-40} =\frac{-40}{-40} \\\\\frac{x}{-10}+\frac{y}{-8} =1[/tex]
