[tex](-\frac{4}{15})(\frac{5}{8} ) :(- \frac{1}{6} )\\\\(-\frac{20}{120} ) :(- \frac{1}{6} )\\\\(-\frac{2}{12} ) :(- \frac{1}{6} )\\\\(-\frac{1}{16} ) :(- \frac{1}{6} )\\\\(-\frac{1}{6} ) (- \frac{6}{1} )\\\\\frac{6}{6} \\\\1[/tex]
La respuesta es la A)
Eternamente
☆༒ axllxa ༒☆
