Respuesta:
Diámetro que debe tener = 1.1920
Explicación:
[tex]d_{2}[/tex] = ?
[tex]f_{2}[/tex] = 1758 N
[tex]d_{1}[/tex] = 38 cm × 1m ÷ 100 cm =0.38m
[tex]f_{1}[/tex] = 470 N
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[tex]a_{1}[/tex] = π · [tex]d^{2}[/tex] ÷ 4 = 0.2984m²
a1= 0.2984m²
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[tex]a_{2}[/tex] = [tex]f_{2} . a_{1}[/tex] ÷ [tex]f_{1}[/tex] = 1.116[tex]m^{2}[/tex]
a2= 1.116[tex]m^{2}[/tex]
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[tex]D_{2} = 4[/tex] x [tex]a_{2}[/tex] ÷ [tex]\pi[/tex] = 1.4209[tex]m^{2}[/tex]
d2 = [tex]1.4209m_{2} }[/tex]
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[tex]\sqrt{d_{2} } =[/tex] [tex]\sqrt{1.4209m_{2} }[/tex]
Diametro = 1.1920m
